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# Description The help description on `transpose --header-row/-r` appears to be wrong (and now that I understand that, it probably explains why it's confused me for so long). It currently says: ``` -r, --header-row - treat the first row as column names ``` This just looks wrong - The first **row** of the input data is not considered. It's the first **column** that is used to create the header-row of the transposed table. For example: To record using `-dr`: ```nu [[col-names values ]; [foo 1 ] [bar 5 ] [baz 7 ] [cat -12 ] ] | transpose -dr ╭─────┬─────╮ │ foo │ 1 │ │ bar │ 5 │ │ baz │ 7 │ │ cat │ -12 │ ╰─────┴─────╯ ``` To table using `-r`: ```nu [[col-names values ]; [foo 1 ] [bar 5 ] [baz 7 ] [cat -12 ] ] | transpose -r ╭───┬─────┬─────┬─────┬─────╮ │ # │ foo │ bar │ baz │ cat │ ├───┼─────┼─────┼─────┼─────┤ │ 0 │ 1 │ 5 │ 7 │ -12 │ ╰───┴─────┴─────┴─────┴─────╯ ``` # User-Facing Changes Updates the help description to: ``` -r, --header-row - use the first input column as the table header-row (or keynames when combined with --as-record) ``` # Tests + Formatting - 🟢 `toolkit fmt` - 🟢 `toolkit clippy` - 🟢 `toolkit test` - 🟢 `toolkit test stdlib` # After Submitting N/A